std::reverse_iterator<Iter>::operator=
template< class U > reverse_iterator& operator=( const reverse_iterator<U>& other ); |
(until C++17) | |
template< class U > constexpr reverse_iterator& operator=( const reverse_iterator<U>& other ); |
(since C++17) |
The underlying iterator is assigned the value of the underlying iterator of other, i.e. other.base().
| This overload participates in overload resolution only if |
(since C++20) |
Parameters
| other | - | iterator adaptor to assign |
Return value
*this.
Example
#include <iostream>
#include <iterator>
int main()
{
const int a1[] {0, 1, 2};
int a2[] {0, 1, 2, 3};
short a3[] {40, 41, 42};
std::reverse_iterator<const int*> it1{ std::crbegin(a1) };
it1 = std::reverse_iterator<int*>{ std::rbegin(a2) }; // OK
// it1 = std::reverse_iterator<short*>{ std::rbegin(a3) }; // compilation error:
// incompatible pointer types
std::reverse_iterator<short const*> it2{ nullptr };
it2 = std::rbegin(a3); // OK
// it2 = std::begin(a3); // compilation error: no viable overloaded '='
std::cout << *it2 << '\n';
}
Output:
42
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
|---|---|---|---|
| LWG 3435 | C++20 | the converting assignment operator was not constrained | constrained |
See also
| constructs a new iterator adaptor (public member function) |
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